1.

0.452 g of a metal nitrate gave 0.4378 g of its metal sulphate. Calculate the equivalent weight of the metal.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Mass of the metal nitrate taken = 0.452 g<br/> Mass of the metal sulphate obtained = 0.4378 g <br/> <a href="https://interviewquestions.tuteehub.com/tag/suppose-656311" style="font-weight:bold;" target="_blank" title="Click to know more about SUPPOSE">SUPPOSE</a>, equivalent mass of metal = E Using the relation,<br/> `("Mass of metal nitrate")/("Mass of metal sulphate") = ("Equivalent <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of metal nitrate")/("Equivalent weight of metal sulphate")` <br/> `0.452/0.4378 = (E+ 62)/(E + 48)` <br/> [Eq. weight of `NO_(3)^(-) = (14 + (<a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a> xx 3))/1 = 62` <br/> [Eq. weight of `SO_(4)^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>-) = (32 + (16 xx 4))/2 = 48` <br/> or `0.452-0.4378 xx E = (0.4378 xx 62) -(0.452 xx 48) = 5.4476` <br/> or `E=5.4476/(0.452-0.4378) = 5.4476/0.0142 = 383.6`</body></html>


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