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0.48 g of a sample of a compound containing boron and oxygen contains 0.192 g of boron and 0.288 g of oxygen. What is the percentage composition of the compound ? |
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Answer» Mass of boron present = 0.192 g Mass of oxygen present = 0.288 g Percent of B `= (("0.192 g"))/(("0.48g"))xx100=40%` Percentage of O `=(("0.288 g"))/(("0.48 g"))xx100=60%`. |
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