1.

0.4x + 0.3y = 1.7; 0.7x + 0.2y = 0.8 Solve using substitution method 

Answer»

0.4x+0.3y=1.7...(1),
0.7x−0.2y=0.8....(2).

Multiply both the equations by 10, we get
4x+3y=17...(1)
7x−2y=8...(2)

Multiply (1) by 2 and (2) by 3,
8x+6y=34
21x−6y=24
Adding both the equations
29x=58
x=2

From (1):4×2+3y=17
⇒8+3y=17
⇒3y=17−8=9
y=3

Answer : x=2,y=3



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