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0.5 farady of electricity is passed through CaCl2, the amount of calcium metal deposited on electrode is? A) 10gB) 20gC)30gD)40g |
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Answer» ANSWER 2+ +2e − →Ca Number of moles of Ca= 40g/mol 10g
=0.25mol 1 MOLE Ca requires =2 moles of electrons =2 faradays of electricity. 0.25 mole Ca=2×0.25=0.50 moles of electrons =0.5 faradays of electricity. Hence, 0.5 Faradays of electricity are required to DEPOSIT 10 g of calcium from MOLTEN calcium chloride using inert ELECTRODES |
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