0.5 g mixture of oxalic acid (H_(2)C_(2)O_4)and some sodium oxalate (Na_(2)C_(2)O_4)with some impurities requires 40 ml of 0.1M NaOH for complete neutralization and 6ml of 0.2 M KMnO_4for complete oxidation. Calculate the % of Na_2C_(2)O_4in the mixture

0.5 g mixture of oxalic acid (H_(2)C_(2)O_4)and some sodium oxalate (N

1.	0.5 g mixture of oxalic acid (H_(2)C_(2)O_4)and some sodium oxalate (Na_(2)C_(2)O_4)with some impurities requires 40 ml of 0.1M NaOH for complete neutralization and 6ml of 0.2 M KMnO_4for complete oxidation. Calculate the % of Na_2C_(2)O_4in the mixture
Answer» `90%` ` 26.8%` `40%` `50%` Solution : No. of milli equivalents of `H_(2)C_(2)O_4` = No .of milli equivalents of NaOH = 4 No.of milli equivalents of `H_(2)C_(4)O_(4)+Na_(20)C_(2)O_(4)`= No. of milli equivalents of `KMnO_(4)= 6 xx 0.2 xx 5 = 6` Milli EQUIVALENT of `Na_(2)C_(2)O_(4)= 2` Weight of `Na_(2)C_(2)O_(4)=2xx10^(-3)xx67 =0.134` g % `Na_(2)C_2O_4=(0.134)/(0.5)xx100=26.8`