0.5 g mixture of oxalic acid (H_(2)C_(2)O_4)and some sodium oxalate (Na_(2)C_(2)O_4)with some impurities requires 40 ml of 0.1M NaOH for complete neutralization and 6ml of 0.2 M KMnO_4for complete oxidation. Calculate the % of Na_2C_(2)O_4in the mixture

0.5 g mixture of oxalic acid (H_(2)C_(2)O_4)and some sodium oxalate (N

1.	0.5 g mixture of oxalic acid (H_(2)C_(2)O_4)and some sodium oxalate (Na_(2)C_(2)O_4)with some impurities requires 40 ml of 0.1M NaOH for complete neutralization and 6ml of 0.2 M KMnO_4for complete oxidation. Calculate the % of Na_2C_(2)O_4in the mixture
Answer» <html><body><p> `90%`<br/>` 26.8%`<br/>`40%`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a>%`</p>Solution : No. of milli equivalents of `H_(2)C_(2)O_4` = No .of milli equivalents of NaOH = 4 No.of milli <br/> equivalents of `H_(2)C_(4)O_(4)+Na_(20)C_(2)O_(4)`= No. of <br/> milli equivalents of `KMnO_(4)= <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> xx 0.2 xx 5 = 6` <br/>Milli <a href="https://interviewquestions.tuteehub.com/tag/equivalent-446407" style="font-weight:bold;" target="_blank" title="Click to know more about EQUIVALENT">EQUIVALENT</a> of `Na_(2)C_(2)O_(4)= 2` <br/>Weight of `Na_(2)C_(2)O_(4)=2xx10^(-3)xx67 =0.134` g <br/> % `Na_(2)C_2O_4=(0.134)/(0.5)xx100=26.8`</body></html>