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0.5 M ammonium benzoate is hydrolyzed to 0.25 percent, hence its hydrolysis constant isA. `2.5 xx 10^(-5)`B. `1.5 xx 10^(-4)`C. `3.125 xx 10^(-6)`D. `6.25 xx 10^(-14)` |
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Answer» Correct Answer - C `{:(C_(6)H_(5)COONH_(4),rarr,C_(6)H_(5)COO^(-),+,NH_(2)^(+)),(0.5 - (.25)/(100),,(.25)/(100),,(.25)/(100)):}` According to Ostwald dilution law. `K = (alpha^(2)C)/(1-alpha) " " ( :. alpha = (.25)/(100))` `K = alpha^(2)C " " ( because 1- alpha = "Very small")` `K = (0.25)/(100) xx (0.25)/(100) xx 0.5 , K = 3.125 xx 10^(-6)` |
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