0.5 mol CaCO_3 solid decompose in 500 mL heated in closed vessel at 400 K reaction CaCO_(3(s)) hArr CaO_((s)) + CO_(2(g)) equilibrium constant of K_c = 0.9 "mol L"^(-1). Calculate mol of CO_2 at equilibrium how much percentage of reaction completed ?

0.5 mol CaCO_3 solid decompose in 500 mL heated in closed vessel at 40

1.	0.5 mol CaCO_3 solid decompose in 500 mL heated in closed vessel at 400 K reaction CaCO_(3(s)) hArr CaO_((s)) + CO_(2(g)) equilibrium constant of K_c = 0.9 "mol L"^(-1). Calculate mol of CO_2 at equilibrium how much percentage of reaction completed ?
Answer» SOLUTION :`[CO_2]= 0.45 "MOL L"^(-1)`, 90% decomposition `[CO_2]`= 0.3 mol and 60% REACTION if `CaCO_3` and CaO used in calculation