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0.5 molal aqueous solution of a weak acid (HX) is 20% ionised. If `K_(f)` for water is `1.86K kg mol^(-1)`, the lowering in freezing point of the solution isA. `-1.12 K`B. 0.56 KC. 1.12 KD. `0.56 K` |
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Answer» Correct Answer - C `alpha=(i-1)/(n-1)rArr 0.2=(i-1)/(2-1)rArr i=1.2` `rArr Delta T=ixxK_(f)xx m` |
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