0.5 mole each of two ideal gases A (C_(v.m)= (5)/(2)R) and B (C_(v.m)=3R) are taken in a container and expanded reversibly and adiabtically, during this process temperature of gaseous mixture decreases from 350K and 250K. Find DH (in cal/mol) for the process

0.5 mole each of two ideal gases A (C_(v.m)= (5)/(2)R) and B (C_(v.m)=

1.	0.5 mole each of two ideal gases A (C_(v.m)= (5)/(2)R) and B (C_(v.m)=3R) are taken in a container and expanded reversibly and adiabtically, during this process temperature of gaseous mixture decreases from 350K and 250K. Find DH (in cal/mol) for the process
Answer» <html><body><p>`-100R`<br/>`-137.5R`<br/>`-375R`<br/>none of these</p>Solution :In case of a mixture of gas `C_(P) = (n_(1)Cp_(1) + n_(2)Cp_(2))/(n_(1) n_(2)) = ((0.5) ((<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)/(2)<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)+ 0.5 (4R))/(1)` = 3.75R <br/> `<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> H = nCp Delta T = 1 xx 3.75 xx (-100) = - 375R`</body></html>