0.5 mole of calcium carbonate id decomposed by an aqueous solution containing 25 % JCl by mass. Calculate the mass of the solution consumed.

0.5 mole of calcium carbonate id decomposed by an aqueous solution con

1.	0.5 mole of calcium carbonate id decomposed by an aqueous solution containing 25 % JCl by mass. Calculate the mass of the solution consumed.
Answer» Solution :Chemical equation for the REACTION is : `underset("1 mol")(CaCO_(3))+underset("2 mol")(2HCl)rarrCaCl_(2)+H_(2)O+CO_(2)` 1 mole of `CaCO_(3)` react with HCl = 2 mol 0.5 mole of `CaCO_(3)` react with HCl = 1 mol = 36.5 g Mass of HCl solution REQUIRED ot consumed `= 36.5 xx (100)/(25) = 146 g`.