0.5 mole of calcium carbonate id decomposed by an aqueous solution containing 25 % JCl by mass. Calculate the mass of the solution consumed.

0.5 mole of calcium carbonate id decomposed by an aqueous solution con

1.	0.5 mole of calcium carbonate id decomposed by an aqueous solution containing 25 % JCl by mass. Calculate the mass of the solution consumed.
Answer» <html><body><p><br/></p>Solution :Chemical equation for the <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> is : <br/> `underset("1 mol")(CaCO_(3))+underset("2 mol")(2HCl)rarrCaCl_(2)+H_(2)O+CO_(2)`<br/> 1 mole of `CaCO_(3)` react with HCl = 2 mol <br/> 0.5 mole of `CaCO_(3)` react with HCl = 1 mol = 36.5 g <br/> Mass of HCl solution <a href="https://interviewquestions.tuteehub.com/tag/required-1185621" style="font-weight:bold;" target="_blank" title="Click to know more about REQUIRED">REQUIRED</a> ot consumed `= 36.5 xx (100)/(<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a>) = 146 g`.</body></html>