1.

0.5 mole of P_(4)IO_(10) contains

Answer»

80 gm oxygen
2 gram atoms PHOSPHOROUS
5 gram atoms oxygen
10 gram atoms oxygen

Solution :MOLECULAR weigth of `P_(4)O_(10)=284`
1 mole `P_(4)O_(10)=284g`
`284 g P_(4)O_(10)` contains 124 g phosphorous
`284g P_(4)O_(10)` contain 160 g oxygen
0.5 moles `P_(4)O_(10)-62 g P - 80 g` oxygen
(2 gram atom) (5 gram atom)


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