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0.5 moles of gaseousnon-metallic X^(-) anions (having positive electron affinity) requires 806.4 kJ energy to get completely converted into gaseous X^(+) ions. Calculate Pauling's electronegativity of the elements X. Use Avogardo's no = 6 xx 10^(23) and 1eV = 1.6 xx 10^(-19)J. [Use the fact that, Pauling's electronegativity =("Mulliken's electronegativity")/(2.8) and Mulliken's electronegativity =("Ionisation energy+ Electron affinity")/(2)]

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Let `X rarr X^(+)e^(-)` <br/> `:. <a href="https://interviewquestions.tuteehub.com/tag/ie-496825" style="font-weight:bold;" target="_blank" title="Click to know more about IE">IE</a>` (energy absorbed) = aeV <a href="https://interviewquestions.tuteehub.com/tag/per-590802" style="font-weight:bold;" target="_blank" title="Click to know more about PER">PER</a> atom and `X +e^(-) rarr X^(-)` <br/> `:. EA` (energy <a href="https://interviewquestions.tuteehub.com/tag/released-613817" style="font-weight:bold;" target="_blank" title="Click to know more about RELEASED">RELEASED</a>) =- beV per atom Now `(N)/(2)` of `X^(-)` will lose two elecctrons to give `(N)/(2)X^(+)` <br/> `:. X^(-) rarr X +E^(-)` <br/> `:.` energy absorbed `= + beV` per atom. <br/> `X rarr X^(+) +e^(-)` <br/> `:.` energy absorbed `=+ aeV` per atom. <br/> `:. a xx (N)/(2) + b xx (N)/(2) = (806.4xx 1000)/(1.6 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-19)) eV` <br/> or `(a+b) = (806.4 xx 1000 xx 2)/(1.6 xx 10^(-19) xx 6 xx 10^(23)) = (806.4 xx 2)/(1.6 xx 60) = 16.8` <br/> `xhi_(m) = (IE +EA)/(2) = (16.8)/(2) = 8.4` <br/> `:.` Mulliken's electronegativity = 8.4 <br/> Pauling's electronegativity `= (8.4)/(2.8) = 3.0`</body></html>


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