1.

0.50 g of an organic compound was Kjeldahlished. The ammonia evolved was passed in 50 cm^(3) of 1N H_(2)SO_(4). The residual acid required 60 cm^(3) of N // 2 NaOH solution. Calculate the percentage of nitrogen in the compound.

Answer» <html><body><p></p>Solution :Step 1. <a href="https://interviewquestions.tuteehub.com/tag/calculation-907729" style="font-weight:bold;" target="_blank" title="Click to know more about CALCULATION">CALCULATION</a> of volume of unused acid <br/> `"Volume of NaOH solution required" = 60 cm^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/> `"Normality of NaOH solution" =(1)/(2)N` <br/> `"Normality of" H_(2)SO_(4) "solution"= (1)/(N)` <br/> Volume of unused acid can be calculated by applying normality equation <br/> `underset("Acid")(underbrace(N_(1)V_(1)))=underset("<a href="https://interviewquestions.tuteehub.com/tag/base-892693" style="font-weight:bold;" target="_blank" title="Click to know more about BASE">BASE</a>")(underbrace(N_(1)V_(1)))` <br/> `1 xx V=(1)/(2) xx 60 = 30 cm^(3)` <br/> Step II. Calculation of volume of acid used <br/> `"Volume of acid added" = 50 cm^(3)` <br/> `"Volume of unused acid" = 30 cm^(3)` <br/> `"Volume of acid used"= (50-30) = 20 cm^(3)` <br/> Step III. Calculation of percentage of <a href="https://interviewquestions.tuteehub.com/tag/nitrogen-1118291" style="font-weight:bold;" target="_blank" title="Click to know more about NITROGEN">NITROGEN</a> <br/> Mass of compound = 0.50 g <br/> `"Volume of acid used"=20 cm^(3)` <br/> Normality of acid used = 1 N <br/> `"Percentage of N" = (1.4 xx "Volume of acid used" xx "Normality of acid used")/("Mass of the compound")` <br/> `=(1.4 xx 20 xx 1)/(0.50)=50%`</body></html>


Discussion

No Comment Found

Related InterviewSolutions