0.532 g of the chloroplatinate of an organic base (mol.wt 24 D) gave 0.195 g of Pt on ignition. Then the number of nitrogen atoms per molecule of the base is

0.532 g of the chloroplatinate of an organic base (mol.wt 24 D) gave 0

1.	0.532 g of the chloroplatinate of an organic base (mol.wt 24 D) gave 0.195 g of Pt on ignition. Then the number of nitrogen atoms per molecule of the base is
Answer» <html><body><p>1<br/>2<br/>3<br/>4</p>Solution :`(<a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a>)/(2E+410)=(<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/195-281683" style="font-weight:bold;" target="_blank" title="Click to know more about 195">195</a>)`<br/>`(0.532)/(2E+410)=(0.195)/(195)<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> E=61`</body></html>