0.532 gram of chloroplatinate of an organic base (mol wt. 244) gave 0.195 gram of platinum on ignition. Thenumber of nitrogen atoms per molecule of base is(d)(d) 4(b) 2(c) 3(a) 1(OJEE) plz solve this

0.532 gram of chloroplatinate of an organic base (mol wt. 244) gave

1.	0.532 gram of chloroplatinate of an organic base (mol wt. 244) gave 0.195 gram of platinum on ignition. Thenumber of nitrogen atoms per molecule of base is(d)(d) 4(b) 2(c) 3(a) 1(OJEE) plz solve this
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