1.

0.548 g of the metal reacts with dilute acid and liberates 0.0198 g of hydrogen at S.T.P. Calculate the equivalent mass of the metal.

Answer»

Solution :0.548 g of the METAL DISPLACES 0.0198 g of hydrogen
The mass of the metal which will DISPLACE
1.008 g of hydrogen ` = (1.008 xx 0.548)/( 0.0198)g` of metal
The equivalent mass of the metal `=27.90 g"equiv"^(-1)` .


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