1.

0.56 g of a gas occupies `280 cm^(3)` at N.T.P., then its molecular mass isA. `4.8`B. `44.8`C. `2`D. `22.4`

Answer» Correct Answer - B
`280 cm^(3)` of the gas at N.T.P. has mass = 0.56g
`:. 22400 cm^(3)` of the gas at N.T.P. has mass
`= (0.56g)/(280cm^(3))xx22400cm^(3)`
`= 44.8 g`
`:.` Molecular mass of the gas = 44.8


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