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`0.56 g` of lime stone was treated with oxalic acid to give `CaC_(2)O_(4)`. The precipitate decolorized `45 ml` of `0.2N KMnO_(4)` in acid medium. Calculate `%` of `CaO` in lime stone. |
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Answer» `underset(CaCO_(3))("Limestone")overset("Oxalic acid")rarrCaC_(2)O_(4)overset(KMnO_(4))rarr"decolorizes"` `therefore` Redox changes: For `CaC_(2)O_(4), C_(2)^(3+)rarr2C^(4+)+2e` For `KMnO_(4), 5e+Mn^(7+)rarrMn^(2+)` `therefore` Meq.of `CaCO_(3)=` Meq.of `CaC_(2)O_(4)=` meq.of `KMnO_(4)` `because` Meq.of `CaCO_(3)=` Meq.of `CaO` ( since `CaO` is present in `CaCO_(3)`) `therefore` Meq.of `CaO=` Meq.of `KMnO_(4)` `(w)/(56//2)xx1000=45xx0.2` Wt.of `CaO=0.252g` `therefore %` of `CaO` in limestone `=(0.252)/(0.56)xx100=45%` |
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