0.59 g of an organic compound produces 112 mL nitrogen at NTP. The percentage of nitrogen in the compound through Duma's method is

0.59 g of an organic compound produces 112 mL nitrogen at NTP. The per

1.	0.59 g of an organic compound produces 112 mL nitrogen at NTP. The percentage of nitrogen in the compound through Duma's method is
Answer» 23.7 27.5 33.07 16.8 Solution :`%` of N through Duma's method is GIVEN by `%` of `=N=(28xx"VOLUME of " N_(2)" at STP")/(22400 xx "Mass of an ORGANIC compound")xx100` `=(28xx112xx100)/(22400xx0.59)=23.7`.