0.59 g of an organic compound produces 112 mL nitrogen at NTP. The percentage of nitrogen in the compound through Duma's method is

0.59 g of an organic compound produces 112 mL nitrogen at NTP. The per

1.	0.59 g of an organic compound produces 112 mL nitrogen at NTP. The percentage of nitrogen in the compound through Duma's method is
Answer» <html><body><p>23.7<br/>27.5<br/>33.07<br/>16.8</p>Solution :`%` of N through Duma's method is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> by <br/> `%` of `=N=(28xx"<a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of " N_(2)" at <a href="https://interviewquestions.tuteehub.com/tag/stp-633132" style="font-weight:bold;" target="_blank" title="Click to know more about STP">STP</a>")/(22400 xx "Mass of an <a href="https://interviewquestions.tuteehub.com/tag/organic-1138713" style="font-weight:bold;" target="_blank" title="Click to know more about ORGANIC">ORGANIC</a> compound")xx100` <br/> `=(28xx112xx100)/(22400xx0.59)=23.7`.</body></html>