1.

`0.5F` of electricity is passed through `500mL` of copper sulphate solution. The amount of copper which can be deposited will beA. ` 63. 5G`B. ` 31. 75 g`C. ` 15. 8g`D. Unpredictable

Answer» Correct Answer - C
`Cu^(2+) +2e rarr Cu`
` 2F=1 mol of Cu = 63. 5 g ` of `Cu`
` 0.5 F= (63.5)/2 xx 0 =15 . 8 g` .


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