1.

0.6% solution of urea and 1.8% solution containing a solute (A) are isotonic with each other. Calculate the molecular weight of the solute (A).

Answer»

SOLUTION :`X=0.6% y=1.8%, M_(x)="UREA" (60 g "mol"^(-1)),M_(y)=?`
`(x)/(100)xx(100)/(M_(x))=(y)/(100)xx(100)/(M_(y))=(x)/(M_(x))=(y)/(M_(y))`
`M_(y)=(y xx M_(x))/(x)=(1.8xx60 g "mol"^(-1))/(0.6)`
`=180 g "mol"^(-1)`


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