0.635g of a cupric salt was dissolved in water, excess of KI was a

1.	0.635g of a cupric salt was dissolved in water, excess of KI was added and the liberated iodine required 25ml of N/5Na2S2O3N solution the weight percentage of copper in the salt is ?
Answer» The number of Cu²⁺ = 25 × 1/5 = 5 = Number of milli moles The weight of the copper in cupric salt is: ⇒ 5 × 63.5 × 10^-3 = 0.3175 g Now, the weight of the copper in 0.635 g of a cupric salt is: ⇒ 0.3175/0.635 = 0.5 g now, the weight percentage is: ⇒ 0.5 × 100% = 50%

0.635g of a cupric salt was dissolved in water, excess of KI was added and the liberated iodine required 25ml of N/5Na2S2O3N solution the weight percentage of copper in the salt is ?

Answer»

The number of Cu²⁺ = 25 × 1/5 = 5 = Number of milli moles

The weight of the copper in cupric salt is:

⇒ 5 × 63.5 × 10^-3 = 0.3175 g

Now, the weight of the copper in 0.635 g of a cupric salt is:

⇒ 0.3175/0.635 = 0.5 g

now, the weight percentage is:

⇒ 0.5 × 100% = 50%

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0.635g of a cupric salt was dissolved in water, excess of KI was added and the liberated iodine required 25ml of N/5Na2S2O3N solution the weight percentage of copper in the salt is ?

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