0.66 g of H_(3)PO_(2) will require x ml of 0.1M NaOH for complete neutralization. X is

0.66 g of H_(3)PO_(2) will require x ml of 0.1M NaOH for complete neut

1.	0.66 g of H_(3)PO_(2) will require x ml of 0.1M NaOH for complete neutralization. X is
Answer» 100 ml 200 ml 300 ml none of these Solution :eq. `H_(3PO_(2)` = eq. NaOH `(0.66)/(66)XX1=(x xx0.1)/(1000)xx1impliesx 100mL`