0.759 g of silver salt of a dibasic acid was ignited to form 0.463 g of the silver residue. Calculate the molecular mass of the acid.

0.759 g of silver salt of a dibasic acid was ignited to form 0.463 g o

1.	0.759 g of silver salt of a dibasic acid was ignited to form 0.463 g of the silver residue. Calculate the molecular mass of the acid.
Answer» <html><body><p></p>Solution :Step 1: <a href="https://interviewquestions.tuteehub.com/tag/equivalent-446407" style="font-weight:bold;" target="_blank" title="Click to know more about EQUIVALENT">EQUIVALENT</a> <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of silver salt of the acid. <br/> Equivalent mass of silver salt of the acid `= ("Mass of silver salt")/("Mass of silver residue") xx <a href="https://interviewquestions.tuteehub.com/tag/108-266746" style="font-weight:bold;" target="_blank" title="Click to know more about 108">108</a>` <br/> `= (0.759)/(0.463) xx 108 = 177` <br/> Step II. Equivalent mass of acid <br/> Equivalent mass of acid `=` Equivalent mass of silver salt - Equivalent mass of Ag + Equivalent mass of H <br/> `= 177 - 108 + 1 = 70` <br/> Step III. Molecular mass of acid <br/> Molecular mass of acid = Equivalent mass `xx` basicity <br/> `= 70 xx 2 = <a href="https://interviewquestions.tuteehub.com/tag/140-273392" style="font-weight:bold;" target="_blank" title="Click to know more about 140">140</a>`</body></html>