0.759 g of silver salt of a dibasic acid was ignited to form 0.463 g of the silver residue. Calculate the molecular mass of the acid.

0.759 g of silver salt of a dibasic acid was ignited to form 0.463 g o

1.	0.759 g of silver salt of a dibasic acid was ignited to form 0.463 g of the silver residue. Calculate the molecular mass of the acid.
Answer» Solution :Step 1: EQUIVALENT MASS of silver salt of the acid. Equivalent mass of silver salt of the acid `= ("Mass of silver salt")/("Mass of silver residue") xx 108` `= (0.759)/(0.463) xx 108 = 177` Step II. Equivalent mass of acid Equivalent mass of acid `=` Equivalent mass of silver salt - Equivalent mass of Ag + Equivalent mass of H `= 177 - 108 + 1 = 70` Step III. Molecular mass of acid Molecular mass of acid = Equivalent mass `xx` basicity `= 70 xx 2 = 140`