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0.76 gram mixture of H2 and O2 occupy 2000 cm3 of volume at 300K and 105 Pascal pressure, then molar ratio of Hydrogen and oxygen is |
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Answer» For mixture. PV = nRT 1 x 2 = nTotal x 1/12 x 300 nTotal = 24/300 = 0.08 Mole \(n_{H_{2}}\)+ \(n_{O_{2}}\) = 0.08 (i) \(W_{H_{2}}\) + \(W_{O_{2}}\)= 0.76 (ii) \(W_{H_{2}}\)/2 + \(W_{O_{2}}\)/32 = 0.08 16\(W_{H_{2}}\) + \(W_{O_{2}}\)= 0.08 x 32; \(W_{H_{2}}\) = (0.08 x 32 - 0.76 / 15) = 0.12 ; \(W_{O_{2}}\) = 0.64 So \(n_{H_{2}}\) = 0.12/2 = 0.06 ; \(n_{o_{2}}\) = 0.64 / 32 = 0.02 = 3 |
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