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0.79 g of iron unite directly with 0.4 g sulphur to form ferrous sulphate. If 2.8 g of iron are dissolved in dilute HCl and excess of sodium sulphide solution is added, 4.4 g iron sulphite is precipitated. Show that the data is according to Law of constant composition.

Answer» <html><body><p></p>Solution :In the first sample : <br/> Ratio by mass of <a href="https://interviewquestions.tuteehub.com/tag/iron-1051344" style="font-weight:bold;" target="_blank" title="Click to know more about IRON">IRON</a> and sulphur is : 0.<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a> : 0.4 or 7 : 4 <br/> In the second sample <br/> Mass of iron dissolved = 2.8 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> <br/> Mass of iron sulphide formed = 4.4 g <br/> Mass of sulphuric reacted `= (4.4 - 2.8) = 1.6 g` <br/> Ratio of mass of iron and sulphur is : 2.8 : 1.6 or 7 : 4 <br/> Since the ratio by mass of Fe and S in the <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> samples is the same, this <a href="https://interviewquestions.tuteehub.com/tag/verifies-1444819" style="font-weight:bold;" target="_blank" title="Click to know more about VERIFIES">VERIFIES</a> the Law of constant composition.</body></html>


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