0.900g of a solute was dissolved in 100 ml of benzene at 25^(@)C when its density is 0.879 g/ml. This solution boiled 0.250^(@)C higher than the boiling point of benzene. Molal elevation constant for benzene is "2.52 K.Kg.mol"^(-1). Calculate the molecular weight of the solute.

0.900g of a solute was dissolved in 100 ml of benzene at 25^(@)C when

1.	0.900g of a solute was dissolved in 100 ml of benzene at 25^(@)C when its density is 0.879 g/ml. This solution boiled 0.250^(@)C higher than the boiling point of benzene. Molal elevation constant for benzene is "2.52 K.Kg.mol"^(-1). Calculate the molecular weight of the solute.
Answer» SOLUTION :`"Weight of benzene "=100xx0.879=87.9g` Molality of solution, m `=(0.900//M_(2))/(87.9)xx1000` `=(900)/(87.9M_(2))` `DeltaT_(b)=K_(b)m" (or)0.52"XX(900)/(87.9M_(2))` `therefore""M_(2)=(900xx2.52)/(87.9xx0.250)` `M_(2)="103.2g/mole"` `therefore""{:("Molecular weight"),("of the SOLUTE"):}}="103.2 g/mole"`