0.900g of a solute was dissolved in 100 ml of benzene at 25^(@)C when its density is 0.879 g/ml. This solution boiled 0.250^(@)C higher than the boiling point of benzene. Molal elevation constant for benzene is "2.52 K.Kg.mol"^(-1). Calculate the molecular weight of the solute.

0.900g of a solute was dissolved in 100 ml of benzene at 25^(@)C when

1.	0.900g of a solute was dissolved in 100 ml of benzene at 25^(@)C when its density is 0.879 g/ml. This solution boiled 0.250^(@)C higher than the boiling point of benzene. Molal elevation constant for benzene is "2.52 K.Kg.mol"^(-1). Calculate the molecular weight of the solute.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`"Weight of benzene "=100xx0.879=87.9g` <br/> Molality of solution, m `=(0.900//M_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(87.9)xx1000` <br/> `=(900)/(87.9M_(2))` <br/> `DeltaT_(b)=K_(b)m" (or)0.52"<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>(900)/(87.9M_(2))` <br/> `therefore""M_(2)=(900xx2.52)/(87.9xx0.250)` <br/> `M_(2)="103.2g/mole"` <br/> `therefore""{:("Molecular weight"),("of the <a href="https://interviewquestions.tuteehub.com/tag/solute-1217068" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTE">SOLUTE</a>"):}}="103.2 g/mole"`</body></html>