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0.92 g of an organic compound was analysed by combustion method. The mass of the U-tube increased by 1.08 g. what is the percentage of hydrogen in the compound? |
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Answer» 0.1304 18g `H_(2)O-=2` g H `1.08" g "H_(2)O=(2)/(18)xx1.08` % of hydrogen=`(2)/(18)xx(1.08)/(0.92)xx100=13.04%` |
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