0211h: 31 m.In dilute H2SO4 medium H2O2 reducesMnO4 ion to – InterviewSolution

InterviewSolution

1.	0211h: 31 m.In dilute H2SO4 medium H2O2 reducesMnO4 ion to
Answer» s change in the oxidation number of MN from + 7 to +2 due to the reduction that takes place.Explanation:the balanced CHEMICAL reaction for the EQUATION is given below.1 H2SO4 + MnO4- + H2O2 → H2O + O2 + SO4 -2 + MnSO4Hydrogen peroxide acts as a reduced oxidizing agent it in case of this reaction in acidic medium. sulphuric acid it is added to make the medium acidic. there is conversion of MANGANATE to manganese cation. In addition to this HYDROGEN peroxide is broken down into water and oxygen.To know more ,Why does hydrogen peroxide decompose much faster than the ...brainly.in/question/3101002

Discussion

No Comment Found

Related InterviewSolutions

How have the people of the Community helped one another ? What role do the women of Kalikuda play during these daysClass-9th, Moment book, NCERT, CBSE, ‘Weathering The Strom In Ersana’
Write the electronic configuration for Chlorine atom shown belowneed answer
Write the electronic configuration for the atom shown below.
How many electrons are there in the Valence shell of the structure shown below?urgent!!!!!!!!!!!!!!!!!!!!!nowwwwwwwww
One property of Halogen is its Density increases down the group. Give other two physical Properties of Halogen.plz get to the point
Write the relationship between number of moles (n) and atomic mass (n)
In two or more complete sentences explain how to balance the chemical equation,Ca + N2 ⟶ Ca3 + N2 and include all steps.
What is the difference between rate of percolation and water retained
Can anyone help me?this question is from chemistry subject 9th class (Sri Chaitanya)school CBSE board syllabustopic chemical kinetics don't give worest answers okk I will report
practical on conservation of Mass of chemical reaction between copper sulphate and sodium sulphide in aqueous solution