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03) Vapour pressure of chloroform (CHCL,) anddichloromethane (CH,Cl) at 298 K are 200mm Hg and 415 mm Hg respectively. Molefraction of each component in vapour phasea) 0.5 and 0.5b) 0.6 and 0.4c) 0.15 and 0.85d) 0.82 and 0.18

Answer»

Molar mass of chloroform CHCl3= (1 * 12) + (1 * 1) + (3 * 35.5) = 119.5 g/mol

Molar mass of dichloromethane CH2Cl2= (1 * 12) + (2 * 1) + (2 * 35.5) = 85 g/mol

Moles of CHCl3= 25.5/119.5 = 0.213 mol

Moles of CH2Cl2= 40/85 = 0.47 mol

Total number of moles = 0.683 mol

Mole fraction of CH2Cl2= 0.47/0.683 = 0.688

Mole fraction of CHCl3= 1 - 0.688 = 0.312



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