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03) Vapour pressure of chloroform (CHCL,) anddichloromethane (CH,Cl) at 298 K are 200mm Hg and 415 mm Hg respectively. Molefraction of each component in vapour phasea) 0.5 and 0.5b) 0.6 and 0.4c) 0.15 and 0.85d) 0.82 and 0.18 |
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Answer» Molar mass of chloroform CHCl3= (1 * 12) + (1 * 1) + (3 * 35.5) = 119.5 g/mol Molar mass of dichloromethane CH2Cl2= (1 * 12) + (2 * 1) + (2 * 35.5) = 85 g/mol Moles of CHCl3= 25.5/119.5 = 0.213 mol Moles of CH2Cl2= 40/85 = 0.47 mol Total number of moles = 0.683 mol Mole fraction of CH2Cl2= 0.47/0.683 = 0.688 Mole fraction of CHCl3= 1 - 0.688 = 0.312 |
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