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( 05" ÂŽ oQ& |
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Answer» ∫cos⁴xdx=∫cos²xdx−∫sin²xcos²xdx=1/2∫1+cos(2x)dx−1/8∫1−cos(4x)dx=3/8x+1/4sin(2x)+1/32sin(4x)+C ∫ |
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