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06. When 96500 coulombs of electricity is passed throughCuSO4 solution, the metal deposited will be equal to its(A) Gram equivalent weight(B) Gram molecular weight(C) 1gm of metal(D) Electrochemical equivalent

Answer»

At the cathodeCu2+ (aq) + 2e- ---> Cu(s)

At the anode4OH-(aq) ----> 2H2O (l) + O2(g) + 4e-

Faraday’s constant = 96500C/molTo deposit 1 mole of copper, we need 2x96500CSo, 96500C will deposit 0.5 moles of copper = 0.5x63.5 = 31.75gTo liberate one mole of oxygen molecules,we need 4x96500CSo, 96500C will liberate = ¼ = 0.25 moles = 0.25x32 = 8g



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