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06. When 96500 coulombs of electricity is passed throughCuSO4 solution, the metal deposited will be equal to its(A) Gram equivalent weight(B) Gram molecular weight(C) 1gm of metal(D) Electrochemical equivalent |
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Answer» At the cathodeCu2+ (aq) + 2e- ---> Cu(s) At the anode4OH-(aq) ----> 2H2O (l) + O2(g) + 4e- Faraday’s constant = 96500C/molTo deposit 1 mole of copper, we need 2x96500CSo, 96500C will deposit 0.5 moles of copper = 0.5x63.5 = 31.75gTo liberate one mole of oxygen molecules,we need 4x96500CSo, 96500C will liberate = ¼ = 0.25 moles = 0.25x32 = 8g |
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