06238, In Fig 138, ABCD is a square of side 2n Find the ratio betweers

1.	06238, In Fig 138, ABCD is a square of side 2n Find the ratio betweers) theiciumderecesthe areas of the incircle and the circum-circle of the squareFin 13 98
Answer» We have a square ABCD havingAb = 2a From the given diagram we can observe that, Radius of incircle r1 = a Radius of circumcircle r2 = √2a (i) We have to find the ratio of the circumferences of the two circles. So the required ratio is, = perimeter of inner circle/perimeter of circumcircle = 2π(a)/2π(√2a) = 1/√2 (ii) We have to find the ratio of the areas of the two circles. So the required ratio is, = area of inner circle/area of circumcircle = π(a)²/π(√2a)² = 1/2 Like my answer if you find it useful!

06238, In Fig 138, ABCD is a square of side 2n Find the ratio betweers) theiciumderecesthe areas of the incircle and the circum-circle of the squareFin 13 98

Answer»

We have a square ABCD havingAb = 2a

From the given diagram we can observe that,

Radius of incircle r1 = a

Radius of circumcircle r2 = √2a

(i) We have to find the ratio of the circumferences of the two circles. So the required ratio is,

= perimeter of inner circle/perimeter of circumcircle

= 2π(a)/2π(√2a)

= 1/√2

(ii) We have to find the ratio of the areas of the two circles. So the required ratio is,

= area of inner circle/area of circumcircle

= π(a)²/π(√2a)²

= 1/2

Like my answer if you find it useful!