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07. If one zero of the polynomial (a+ 9) a + 13k + 6a is reclprocal of the other,find the valuc of a

Answer»

If one of the zero is reciprocal of the other,let one zero beαother zero will be 1/α

Product of roots = c/a⇒α× 1/α = 6a/(a²+9)⇒ 1 = 6a/(a²+9)⇒ a² + 9 = 6a⇒ a² - 6a + 9 = 0⇒ a² - 3a - 3a + 9= 0⇒ a(a-3) -3(a-3) = 0⇒ (a-3)(a-3) = 0⇒ (a-3)²= 0⇒ a = 3

Value of a is 3.



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