0ETSIn the given figure, PA and PB are tangents to the circle from an

1.	0ETSIn the given figure, PA and PB are tangents to the circle from an externalpoint P. CD is another tangent touching the circle at Q. If PA-12 cmC-QD-3 cm, then find PC+PD.
Answer» Answer: We know that:- Tangent from an external point to a circle are equal, ∴ PA=PB -----eq (1) ∴ CA = CQ----eq(2) ∴DB=DQ--------eq(3) Step-by-step explanation: From the figure we know that PA=PC+AC PA=PC+QC [∵ from eq(2) we know that QC=AC] Substituting the given values, we get 12=PC+3 PC= 9cm Similarly we can find PB PB=PD+DB PB=PD+QD 12=PD+3 PD=9cm So PC+PD= 9+9=18cm So 18 cm is the our answer. Enjoy Maths!

0ETSIn the given figure, PA and PB are tangents to the circle from an externalpoint P. CD is another tangent touching the circle at Q. If PA-12 cmC-QD-3 cm, then find PC+PD.

Answer»

Answer:

We know that:-

Tangent from an external point to a circle are equal,

∴ PA=PB -----eq (1)

∴ CA = CQ----eq(2)

∴DB=DQ--------eq(3)

Step-by-step explanation:

From the figure we know that

PA=PC+AC

PA=PC+QC [∵ from eq(2) we know that QC=AC]

Substituting the given values, we get

12=PC+3

PC= 9cm

Similarly we can find PB

PB=PD+DB

PB=PD+QD

12=PD+3

PD=9cm

So PC+PD= 9+9=18cm

So 18 cm is the our answer.

Enjoy Maths!