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0x61 + 0 results in _____________(a) 0(b) ‘a’(c) 97(d) arbitrary |
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Answer» The correct choice is (c) 97 The best explanation: The hexadecimal constants are treated as binary strings unless the context indicates a number. In the string contexts, each pair of hexadecimal digits is converted to a character, then the result is used as a string. |
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