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1.0 g of magnesium is burnt with 0.56 g O_(2) in a closed vessel. Which reaction is left in excess and how much ? ( At. wt. Mg = 24, O = 16) |
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Answer» `MG, 0.16 g ` `(1.0)/(24) (0.56)/(32)` Oxygen is LIMITING reagent so `(0.5)/(12) - x(0.07)/(4) - x/2` `(0.07)/(4) - x/2 = 0` `x=(0.07)/(2)` excess `Mg=(0.5)/(12) - (0.07)/(2)` mole `rArr 1-0.7xx12= 0.16g` |
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