1.0 g of magnesium is burnt with 0.56 g O_(2) in a closed vessel. Which reaction is left in excess and how much ? ( At. wt. Mg = 24, O = 16)

1.0 g of magnesium is burnt with 0.56 g O_(2) in a closed vessel. Whic

1.	1.0 g of magnesium is burnt with 0.56 g O_(2) in a closed vessel. Which reaction is left in excess and how much ? ( At. wt. Mg = 24, O = 16)
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>, 0.16 g `<br/>`O_(2), 0.16 g`<br/>`Mg, 0.16 g`<br/>`O_(2), 0.28 g`</p>Solution :`M g + 1/2 O_(2) <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> MgO` <br/> `(1.0)/(<a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a>) (0.56)/(<a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a>)` <br/> Oxygen is <a href="https://interviewquestions.tuteehub.com/tag/limiting-2791961" style="font-weight:bold;" target="_blank" title="Click to know more about LIMITING">LIMITING</a> reagent so `(0.5)/(12) - x(0.07)/(4) - x/2` <br/> `(0.07)/(4) - x/2 = 0` <br/> `x=(0.07)/(2)` <br/> excess `Mg=(0.5)/(12) - (0.07)/(2)` mole <br/> `rArr 1-0.7xx12= 0.16g`</body></html>