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1.0 g of magnesium is burnt with 0.56 g `O_(2)` in a closed vessel. Which reactant is left in excess and how much?A. (a)`Mg, 0.16 g`B. (b)`O_(2), 0.16 g`C. (c )`Mg, 0.44 g`D. (d)`O_(2), 0.28 g` |
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Answer» Correct Answer - d The balanced chemical equation is `Mg+1/2O_(2) rarr MgO` `24 g 16 g 40 g` From the above equation, it is clear that, `24 g Mg` reacts with `16 g O_(2)`. Thus, `1.0 g Mg` reacts with `16/24xx0.67 g O_(2)=0.67 g O_(2)` But only `0.56 g O_(2)` is available which is less than `0.67 g`. Thus, `O_(2)` is the limiting reagent. Further, `16 g O_(2)` reacts with `24 g Mg`. `:. 0.56 g O_(2)` react with `Mg=24/16xx0.56=0.84 g` :. Amount of Mg left unreacted`=1.0-0.84 g Mg` `=0.16 g Mg`. Hence, Mg is present in excess and 0.16 g Mg is left behind unreacted. |
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