1.

1.0 g of magnesium is burnt with 0.56 g `O_(2)` in a closed vessel. Which reactant is left in excess and how much?A. (a)`Mg, 0.16 g`B. (b)`O_(2), 0.16 g`C. (c )`Mg, 0.44 g`D. (d)`O_(2), 0.28 g`

Answer» Correct Answer - d
The balanced chemical equation is
`Mg+1/2O_(2) rarr MgO`
`24 g 16 g 40 g`
From the above equation, it is clear that, `24 g Mg` reacts with `16 g O_(2)`.
Thus, `1.0 g Mg` reacts with
`16/24xx0.67 g O_(2)=0.67 g O_(2)`
But only `0.56 g O_(2)` is available which is less than `0.67 g`.
Thus, `O_(2)` is the limiting reagent.
Further, `16 g O_(2)` reacts with `24 g Mg`.
`:. 0.56 g O_(2)` react with `Mg=24/16xx0.56=0.84 g`
:. Amount of Mg left unreacted`=1.0-0.84 g Mg`
`=0.16 g Mg`.
Hence, Mg is present in excess and 0.16 g Mg is left behind unreacted.


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