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1.0 g of magnesium is burnt with 0.56 g of O_(2) in a closed vessel. Which reactant is left in excess and how much ? |
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Answer» Mg , 0.44 g 32 g of `O_(2)` react with Mg = 48 g 0.56 g of `O_(2)` react with `Mg=((48G))/((32g))xx(0.56g)` Mass of mg TAKEN `= 1.0 g` Mass of Mg LEFT `= (1- 0.84) = 0.16 g`. |
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