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1.0 g of magnesium is burnt with 0.56 g of O_(2) in a closed vessel. Which reactant is left in excess and how much ?

Answer» <html><body><p>Mg , 0.44 g<br/>`O_(2)` , 0.28 g<br/>Mg , 0.16 g<br/>`O_(2)` , 0.16 g</p>Solution :`underset(2xx24g)(2Mg)+underset(<a href="https://interviewquestions.tuteehub.com/tag/32g-307750" style="font-weight:bold;" target="_blank" title="Click to know more about 32G">32G</a>)(O_(2))rarr2MgO` <br/> 32 g of `O_(2)` react with Mg = <a href="https://interviewquestions.tuteehub.com/tag/48-318016" style="font-weight:bold;" target="_blank" title="Click to know more about 48">48</a> g <br/> 0.56 g of `O_(2)` react with `Mg=((<a href="https://interviewquestions.tuteehub.com/tag/48g-1880255" style="font-weight:bold;" target="_blank" title="Click to know more about 48G">48G</a>))/((32g))xx(0.56g)` <br/> Mass of mg <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> `= 1.0 g` <br/> Mass of Mg <a href="https://interviewquestions.tuteehub.com/tag/left-1070879" style="font-weight:bold;" target="_blank" title="Click to know more about LEFT">LEFT</a> `= (1- 0.84) = 0.16 g`.</body></html>


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