1.

1.0 g of magnesium is burnt with 0.56 g of O_(2) in a closed vessel. Which reactant is left in excess and how much ?

Answer»

Mg , 0.44 g
`O_(2)` , 0.28 g
Mg , 0.16 g
`O_(2)` , 0.16 g

Solution :`underset(2xx24g)(2Mg)+underset(32G)(O_(2))rarr2MgO`
32 g of `O_(2)` react with Mg = 48 g
0.56 g of `O_(2)` react with `Mg=((48G))/((32g))xx(0.56g)`
Mass of mg TAKEN `= 1.0 g`
Mass of Mg LEFT `= (1- 0.84) = 0.16 g`.


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