1.0 g of non - electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.4 K. Find the molar mass of the solute. [Given : Freezing point depression constant of benzene = 5.12 K. kg mol].

1.0 g of non - electrolyte solute dissolved in 50 g of benzene lowered

1.	1.0 g of non - electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.4 K. Find the molar mass of the solute. [Given : Freezing point depression constant of benzene = 5.12 K. kg mol].
Answer» Solution :`DeltaT_(f)=0.40K` `K_(f)="5.12 kg MOL"^(-1)` `W_(2)=1g` `W_(1)="50.5 gm "=(50.5)/(1000)kg` `M_(2)=(K_(f))/(DeltaT_(f))xx(W_(2))/(W_(1))` `therefore""M_(2)=(5.12)/(0.40)xx(1)/(50.5)xx1000` `="2.56 g mol"^(-1)` Thus, the molecule mass of the solute `=" 256 g mol"^(-1)`.