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1.0 g of non - electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.4 K. Find the molar mass of the solute. [Given : Freezing point depression constant of benzene = 5.12 K. kg mol].

Answer» <html><body><p></p>Solution :`DeltaT_(f)=0.40K` <br/> `K_(f)="5.12 kg <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>"^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> `W_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=1g` <br/> `W_(1)="50.5 gm "=(50.5)/(1000)kg` <br/> `M_(2)=(K_(f))/(DeltaT_(f))xx(W_(2))/(W_(1))` <br/> `therefore""M_(2)=(5.12)/(0.40)xx(1)/(50.5)xx1000` <br/> `="2.56 g mol"^(-1)` <br/> Thus, the molecule mass of the solute `=" 256 g mol"^(-1)`.</body></html>


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