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`1.0 g` of pure calcium carbonate was found to require `50 mL` of dilute `HCl` for complete reactions. The strength of the `HCl` solution is given by:A. 4 NB. 2 NC. 0.4 ND. 0.2 N |
Answer» Correct Answer - C M.eq. of HCl = M.eq. of `CaCO_(3)` `N xx50=(1)/(50)xx1000 , N=(1xx1000)/(50xx50)=0.4 N` |
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