1.0 mole of ethyl alcohol and 1.0 mole of acctic acid are mixed. At equilibrium, 0.666 mole of ester is formed. The value of equilibrium constant is

1.0 mole of ethyl alcohol and 1.0 mole of acctic acid are mixed. At eq

1.	1.0 mole of ethyl alcohol and 1.0 mole of acctic acid are mixed. At equilibrium, 0.666 mole of ester is formed. The value of equilibrium constant is
Answer» `1//4` `1//2` 4 3 Solution :`C_(2)H_(5)OH+CH_(3)COOH harr CH_(3)COOC_(2)H_(5)+H_(2)O` `K_(c)=([CH_(3)COOC_(2)H_(5)][H_(2)O])/([C_(2)H_(5)OH][CH_(3)COOH])` `=(0.666 xx 0.666)/(0.333 xx 0.333)=4`