1.0 mole of pure dinitrogen gas at SATP conditions was put into a vessel of volume 0.025 cm^(3), maintained at the temperature of 50^(@)C, what is the preussre of the gas in the vessel ?

1.0 mole of pure dinitrogen gas at SATP conditions was put into a vess

1.	1.0 mole of pure dinitrogen gas at SATP conditions was put into a vessel of volume 0.025 cm^(3), maintained at the temperature of 50^(@)C, what is the preussre of the gas in the vessel ?
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution : Volume of `1.0` mol of a gas at SATP `(V_(1))=<a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a><a href="https://interviewquestions.tuteehub.com/tag/8xx10-1931283" style="font-weight:bold;" target="_blank" title="Click to know more about 8XX10">8XX10</a>^(-3)m^(3)` <br/> intial condition (SATP) `""` Final condition <br/> `V_(1)=248xx10^(-3)m^(3)"" V_(2)=01 m^(3)` <br/> `P_(1)1 "bar""" P_(2) ?` <br/> `T_(2)<a href="https://interviewquestions.tuteehub.com/tag/298-1834947" style="font-weight:bold;" target="_blank" title="Click to know more about 298">298</a>15 k"" T_(2)<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a>^(@)C32315K`<br/> Acoording to general gas equation. <br/> `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2)) or P_(2) =(P_(1)V_(1)T_(2))/(T_(1)V_(2))` <br/> `:. P_(2)=(10xx248xx10^(-3)xx32315)/(29815xx025)=1076` bar <br/> `:. P_(2) =1076` bar</body></html>