1.0 mole of pure dinitrogen gas at SATP conditions was put into a vessel of volume 0.025 cm^(3), maintained at the temperature of 50^(@)C, what is the preussre of the gas in the vessel ?

1.0 mole of pure dinitrogen gas at SATP conditions was put into a vess

1.	1.0 mole of pure dinitrogen gas at SATP conditions was put into a vessel of volume 0.025 cm^(3), maintained at the temperature of 50^(@)C, what is the preussre of the gas in the vessel ?
Answer» <P> Solution : Volume of `1.0` mol of a gas at SATP `(V_(1))=248XX10^(-3)m^(3)` intial condition (SATP) `""` Final condition `V_(1)=248xx10^(-3)m^(3)"" V_(2)=01 m^(3)` `P_(1)1 "bar""" P_(2) ?` `T_(2)29815 k"" T_(2)50^(@)C32315K` Acoording to general gas equation. `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2)) or P_(2) =(P_(1)V_(1)T_(2))/(T_(1)V_(2))` `:. P_(2)=(10xx248xx10^(-3)xx32315)/(29815xx025)=1076` bar `:. P_(2) =1076` bar