1.00 gm of a mixture having equal number of moles of carbonates of two alkali metals required 44.4 ml of 0.5 N HCl for complete reaction. Atomic weight of one of the metals is 7.00 The number of moles of each metal carbonate in

1.00 gm of a mixture having equal number of moles of carbonates of two

1.	1.00 gm of a mixture having equal number of moles of carbonates of two alkali metals required 44.4 ml of 0.5 N HCl for complete reaction. Atomic weight of one of the metals is 7.00 The number of moles of each metal carbonate in
Answer» `0.1` `0.0111` `0.0055` `0.00275` Solution :Equal moles of carbonates & EQ. `"BASE"_(1)+` eq `"base"_(2)` = eq HCl IMPLIES eq. of each base = 0.0111 implies moles = `(0.0111)/(2)=0.0055`