1.00 gm of a mixture having equal number of moles of carbonates of two alkali metals required 44.4 ml of 0.5 N HCl for complete reaction. Atomic weight of one of the metals is 7.00 The number of moles of each metal carbonate in

1.00 gm of a mixture having equal number of moles of carbonates of two

1.	1.00 gm of a mixture having equal number of moles of carbonates of two alkali metals required 44.4 ml of 0.5 N HCl for complete reaction. Atomic weight of one of the metals is 7.00 The number of moles of each metal carbonate in
Answer» <html><body><p>`0.1`<br/>`0.0111`<br/>`0.0055`<br/>`0.00275`</p>Solution :Equal moles of carbonates & <br/> <a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>. `"<a href="https://interviewquestions.tuteehub.com/tag/base-892693" style="font-weight:bold;" target="_blank" title="Click to know more about BASE">BASE</a>"_(1)+` eq `"base"_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` = eq HCl <br/> <a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> eq. of each base = 0.0111 <br/> implies moles = `(0.0111)/(2)=0.0055`</body></html>