1.

1.0g ofa samplecontaining NaCl, KCl and some inert impurity is dissolvedin excess of water and treated with excess of AgNO_(3) solution. A 2.0 g precipitate to AgCl separate out. Also sample is 23% by mass in sodium. Determine mass percentage of KCl in the sample :

Answer»


Solution :Moles of `NaCl`in SAMPLE `=0.01` = moles of `AgCl` from `NaCl` in PRECIPITATE `=0.01`
Total moles of `AgCl` precipitate `=(2)/(143.5)=0.01393`
implies Moles of `AgCl` from `KCL = 0.00393` = moles of `KCl`
implies Mass of `KCl` in sample `=0.00393xx74.5=0.2928g`
Mass `%` of `KCl` in the sample `=29.28`


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