1.0g sample of subtance A at 100^(@)C is added to 100 mL ofH_(2)O at25^(@)C. Using separate 100 mL portions of H_(2)O , the procedure is repeated with substance B and then with substance C. How will the final temperatures of the water compare ? {:("Substance","Specific heat"),(A,0.60 J g^(-1).^(@)C^(-1)),(B,0.40 J g^(-1).^(@)C^(-1)),(C,0.20 J g^(-1).^(@)C^(-1)):}

1.0g sample of subtance A at 100^(@)C is added to 100 mL ofH_(2)O at25

1.	1.0g sample of subtance A at 100^(@)C is added to 100 mL ofH_(2)O at25^(@)C. Using separate 100 mL portions of H_(2)O , the procedure is repeated with substance B and then with substance C. How will the final temperatures of the water compare ? {:("Substance","Specific heat"),(A,0.60 J g^(-1).^(@)C^(-1)),(B,0.40 J g^(-1).^(@)C^(-1)),(C,0.20 J g^(-1).^(@)C^(-1)):}
Answer» `T_(C) gt T_(B)gt T_(A` `T_(B) gt T_(A)gt T_(C)` `T_(A) gtT_(B)gtT_(C)` `T_(A) =T_(B)=T_(C)` Solution :Specificheat is the amount of heat required to raise the temperature of 1 g of substance through `1^(@)C` or it is the heatreleased when temperature of 1 g of the substance FALLS through `1^(@)C`. Greater the SPECIFIC heat of the substance, greateris th heat released which is absorbed by water and hence greater is the risein temperature of water or greater is the temperature ofwater. As specific heats OFA, B and C are in the order `A gt B gt C`, therefore, `T_(A) gt T_(B) gt T_(C)`