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1.11g CaCl_(2) is added to water forming 500ml of solution 20ml of this solution is taken and diluted 10 folds Find moles of Cl ions in 2ml of diluted solution .

Answer» <html><body><p></p>Solution :`(1.11)/(<a href="https://interviewquestions.tuteehub.com/tag/111-268410" style="font-weight:bold;" target="_blank" title="Click to know more about 111">111</a>) = 0.01 "mol" CaCl_(2)` <br/> Moles of `CaCl_(2)` in 20mlsolution `= (0.01)/(500) xx <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> = (0.01)/(25)` <br/> In `200ml` solution moles of `CaCl_(2) = (0.01)/(25)` [Note Dilution does not change moles of solute] <br/> In `<a href="https://interviewquestions.tuteehub.com/tag/2ml-1837952" style="font-weight:bold;" target="_blank" title="Click to know more about 2ML">2ML</a>` of <a href="https://interviewquestions.tuteehub.com/tag/dilute-431950" style="font-weight:bold;" target="_blank" title="Click to know more about DILUTE">DILUTE</a> solution moles of `CaCl_(2)=(0.01)/(25/(2000))xx2=(0.01)/(2500)=8xx10^(-6)` . <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ALN_CHM_C01_S01_062_S01.png" width="80%"/></body></html>


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