1.11g CaCl_(2) is added to water forming 500ml of solution 20ml of this solution is taken and diluted 10 folds Find moles of Cl ions in 2ml of diluted solution .

1.11g CaCl_(2) is added to water forming 500ml of solution 20ml of thi

1.	1.11g CaCl_(2) is added to water forming 500ml of solution 20ml of this solution is taken and diluted 10 folds Find moles of Cl ions in 2ml of diluted solution .
Answer» Solution :`(1.11)/(111) = 0.01 "mol" CaCl_(2)` Moles of `CaCl_(2)` in 20mlsolution `= (0.01)/(500) xx 20 = (0.01)/(25)` In `200ml` solution moles of `CaCl_(2) = (0.01)/(25)` [Note Dilution does not change moles of solute] In `2ML` of DILUTE solution moles of `CaCl_(2)=(0.01)/(25/(2000))xx2=(0.01)/(2500)=8xx10^(-6)` .