1.

1). 1202). 2403). 2504). 289

Answer»

If digits are all even (0, 2, 4, 6, 8), then we can have 5 × 5 × 5 key values, that is 125 values

Similarly, for odd case (1, 3, 5, 7, 9), we have 125 key values

∴ Possible key values are 250(125+125)



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