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1.16 g sodium chloride should react with how much silver nitrate to form 1.7g sodiumnitrate and 2.87g silver chloride ? |
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Answer»
3.4 g Explanation:
NaCl + AgNO3 -----> AGCL + NaNO3 58.5 + 170 ----> 143.3 + 85
Given MASSES, 1.16 + x ------> 2.87 + 1.7 Comparing AgNO3 and NaNO3 from both reactions, 170 ----> 85 x -----> 1.7 By cross MULTIPLICATION,
x = 3.4 g HOPE THIS HELPS YOU....... |
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