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`1^(2)+1+2^(2)+2+3^(3)+3.........+n^(2)+n =............` |
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Answer» Correct Answer - `(n(n+1)(n+2))/(3)` `=(1^(2)+2^(2)+..........+n^(2))+(1+2+..........+n)` `=(n(n+1)(2n+1))/(6)=(n(n+1))/(2)` `=(n(n+1))/(6)(2n+1+3)=(n(n+1)(n+2))/(3)` |
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