1.

`1^(2)+1+2^(2)+2+3^(3)+3.........+n^(2)+n =............`

Answer» Correct Answer - `(n(n+1)(n+2))/(3)`
`=(1^(2)+2^(2)+..........+n^(2))+(1+2+..........+n)`
`=(n(n+1)(2n+1))/(6)=(n(n+1))/(2)`
`=(n(n+1))/(6)(2n+1+3)=(n(n+1)(n+2))/(3)`


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